6y^2+35y-50=0

Solution for 6y^2+35y-50=0 equation:

6y^2+35y-50=0

a = 6; b = 35; c = -50;
Δ = b2-4ac
Δ = 352-4·6·(-50)
Δ = 2425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2425}=\sqrt{25*97}=\sqrt{25}*\sqrt{97}=5\sqrt{97}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5\sqrt{97}}{2*6}=\frac{-35-5\sqrt{97}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5\sqrt{97}}{2*6}=\frac{-35+5\sqrt{97}}{12}
$